What is the mass in grams of 0.338 mol of glucose (C6H12O6) ? step by step

The amount in mole of a substance = mass in gram * (1 mole of the substance / molar mass of the substance).

molar mass of C6H12O6 = (12*6) + (1*12) + (16*6) = 180.

Let the mass of glucose in gram = G

0.338 = G X (I/180)

0.338 = G/180

G = 0.338 X 180 = 60.84g.