An object traveling a circular path of radius 5 m at constant speed experiences an acceleration of 3 m/s2. If the radius of its path is increased to 10 m, but its speed remains the same, what is its acceleration?

Question

Physics

Bruno Escobar

29 August, 12:04

An object traveling a circular path of radius 5 m at constant speed experiences an acceleration of 3 m/s2. If the radius of its path is increased to 10 m, but its speed remains the same, what is its acceleration?

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Aria Pace · Answer 1

Acceleration = (velocity^2) / Radius. If the radius doubles, then as a result the acceleration halves.

3^2 m/s^2 = velocity^2 m/s / 5 m - > 45 m^2/s^2 = velocity^2 m/s - > velocity = 6.71 m/s

Acceleration = (6.71) ^2 m/s / 10m = 4.5m/s^2