Ask Question
4 April, 01:58

A car moving at 4.5 m/s accelerates at 2.5 m/s2 (The two is squared) After 7s, it will be moving how fast?

+1
Answers (1)
  1. 4 April, 04:59
    0
    The formula is

    V = final velocity = initial velocity U + (acceleration a * time duration t)

    V = U + a t

    = 4.5 m/s + 2.5 m/sec² * 7 sec = 4.5 + 17.5 = 22 m / sec

    Acceleration means, every second the velocity or speed increases by that amount. Here it is 2.5. After one second velocity become 2.5 m/s more. after 2 seconds it is 5 m/s more. after 3 seconds, speed is 7.5 m/s more than at start. Like this after 7 seconds, the speed is 7 * 2.5 higher than at the beginning. so computer the total.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A car moving at 4.5 m/s accelerates at 2.5 m/s2 (The two is squared) After 7s, it will be moving how fast? ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers