A 10 kg box, sliding to the right across a rough horizontal floor, accelerates at - 2 m/s^2 due to the force of friction. Calculate the coefficient of kinetic friction between the box and the floor and the magnitude of the net force acting on the box.

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Physics

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21 January, 23:09

A 10 kg box, sliding to the right across a rough horizontal floor, accelerates at - 2 m/s^2 due to the force of friction. Calculate the coefficient of kinetic friction between the box and the floor and the magnitude of the net force acting on the box.

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Solomon Leonard · Answer 1

According to Newton's second law of motion, Fnet = m x a. From the given above,

Fnet = (10 kg) x (-2 m/s²) = - 20 N

The force of friction, Ff, which is a negative force is the product of the normal force and the coefficient of friction,

Ff = 20 N = k x (10 kg x 9.8 m/s²)

The value of k from the equation is 0.204. Thus, the coefficient of friction is equal to 0.204.