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26 April, 17:39

A lead fishing weight with a mass of 57g absorbs 146 cal of heat. If its initial temperature is 47 degrees Celsius, what is its final temperature?

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  1. 26 April, 20:27
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    The heat and the corresponding difference in the temperature of the system can be related through the equation,

    H = mcp (ΔT)

    where H is heat, m is mass, cp is specific heat and equal to 1 cal/g°C for water, and ΔT is the temperature difference equal to T2 - T1. Substituting the known values,

    146 cal = (57 g) (1 cal / g°C) (T2 - 47°C)

    The value of T2 from the equation is approximately 49.56°C.
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