We want to select a committee of five members from a group of six women and six men. the order of selection is irrelevant. how many committees can we make with fewer men than women? suggestion: there could be three women and two men, four women and one man, or five women.

Question

Finn

3 February, 12:24

+3

Answers (1)

Know the Answer?

Eliza Ross · Answer 1

3 women, 2 men

6C3 * 6C2 = 300

4 women, 1 man

6C4 * 6C1 = 90

5 women, 0 men

6C5 = 6

"or" means to add

300 + 90 + 6 = 396 different committees