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3 February, 12:24

We want to select a committee of five members from a group of six women and six men. the order of selection is irrelevant. how many committees can we make with fewer men than women? suggestion: there could be three women and two men, four women and one man, or five women.

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  1. 3 February, 16:03
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    3 women, 2 men

    6C3 * 6C2 = 300

    4 women, 1 man

    6C4 * 6C1 = 90

    5 women, 0 men

    6C5 = 6

    "or" means to add

    300 + 90 + 6 = 396 different committees
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