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28 February, 16:38

Find five consecutive even integers if the sum of the first and fifth is 2 less than three times the fourth

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  1. 28 February, 17:14
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    If x is the first even integer, the 5 consecutive even integers are

    x, x+2, x+4, x+6, x + 8

    x + (x+8) = 3 (x+6) - 2

    2x+8 = 3x+18-2

    2x+8 = 3x+16

    -x = 8

    x = - 8

    hence the no. s are - 8, - 6, - 4, - 2, 0
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