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29 July, 05:26

What is the kinetic energy (in j) of an n2 molecule moving at this speed?

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  1. 29 July, 06:23
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    1 molecule N2 x (28.0 g / 6.02 x 10^23 molecules) = 4.65 x 10^-23 g = 4.65 x 10^-26 kg/molecule 1. KE = 1/2 m v^2 = 0.5 x 4.65 x 10^-26 kg x (469.4 m/s) ^2 = 5.12 x 10^-21 J/molecule 2 ... kinetic energy = (1/2) m*speed^2
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