If, on average, each person fishing in your local lake catches 3.5 fish per fishing trip, with a standard deviation of 1.2, what are the mean and standard error for a sampling distribution of 30 fishing trips

Mean of sampling distribution=3.5

Standard error of sampling distribution=0.219

Explanation:

We know that

The average of catching fish per fishing trip=μ=3.5

and

The standard deviation of catching fish per fishing trip = σ=1.2.

We have to find the mean and standard error of sampling distribution of 30 fishing trips i. e. μxbar=? and σxbar=?

Mean of sampling distribution=μxbar=μ=3.5

Standard error of sampling distribution=σxbar=σ/√n

Standard error of sampling distribution=σxbar=1.2/√30

Standard error of sampling distribution=σxbar=1.2/5.4772

Standard error of sampling distribution=σxbar=0.219

Thus, the mean and standard error for a sampling distribution of 30 fishing trips are 3.5 and 0.219.