Ask Question
19 January, 18:20

Sin2A + sin2B - sin2C = 4cosA*cosB*cosC

+2
Answers (2)
  1. 19 January, 18:36
    0
    use sin2A as 2sinAcosA and solve
  2. 19 January, 20:56
    0
    Inconclusive

    Explanation:

    Sin2A = Sin (A+A) = SinACosA + CosAsinA=2SinACosA

    Similarly

    Sin2B = 2SinBCosB

    Sin2C=2SinCCosC

    Adding all; we cannot arrive at the expression at the right.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Sin2A + sin2B - sin2C = 4cosA*cosB*cosC ...” in 📘 Social Studies if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers