Ask Question
31 March, 11:53

There are seven seats in each row of a classroom. Luke and Lester are assigned to after-school detention and they must sit in the front row of the classroom, but they cannot sit next to each other because they might talk. How many ways can these two students be seated in the row?

+4
Answers (1)
  1. 31 March, 13:10
    0
    480 Ways

    Explanation:

    Let z represent they must not sit together

    z = (7-1) factorial ways

    z = 6 factorial ways

    Let x = the no. of ways the two children can be seated in 7 seats without seating next to each other

    x = 2*5 factorial ways

    Let y = no of ways the children can be seated on 7 seats, if the must not seat next to each other

    z = x + y

    y = z - x

    y = 6 factorial minus 2*5 factorial

    y = 6*5 factorial minus 2*5 factorial

    y = 5 factorial (6-2)

    y = 5 factorial times 4

    y = 5*4*3*2*1*4

    y = 480 ways.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “There are seven seats in each row of a classroom. Luke and Lester are assigned to after-school detention and they must sit in the front row ...” in 📘 Social Studies if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers