In a hypothetical situation, B is the allele that causes brachydactyly. If a man who has normal fingers (bb) and a woman with brachydactyly (Bb) have children, what proportion of these children would you expect to have normal fingers? (Hint: Use a Punnett square).

Question

Social Studies

Alicia Skinner

27 June, 03:11

In a hypothetical situation, B is the allele that causes brachydactyly. If a man who has normal fingers (bb) and a woman with brachydactyly (Bb) have children, what proportion of these children would you expect to have normal fingers? (Hint: Use a Punnett square).

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Answers (1)

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Michelle Hubbard · Answer 1

2 in 4 children will have normal finger

Explanation:

a cross between the gene for normal finger bb and the gene for brachdactyly Bb will give the result below;

Bb, bb, Bb and bb.

thus 2 in the 4 have normal fingers.