How many moles of nitrogen atoms are there present in 28 grams of Nitrogen gas

Answer:2 * 6.022 * 10²³ atoms.

Explanation:It's 1 mole = mass of the nitrogen

Here we can say, mass of the nitrogen=1mole

1mole=6.022*10^23

And we can get the mass of nitrogen by

Mass of nitrogen=no. Of protons+neutrons

Mass of nitrogen=7+7

Mass of nitrogen=14u

So we get that,

Mass of the nitrogen=1mole

Then,

14g=1mole

28g=xmole

14:28::1:x

14x=28

X=2

So,

28g=2moles