7. In a certain neighborhood of 100 families, 60 get their news from TV, 54 from the local paper, and 20 from both sources. If a family is selected at random, what is the probability that this family does not use any one of these sources for the news?

If a family is selected at random, the probability that this family does not get news from either TV or from local paper = 6% or 6/100

Explanation:

From the given dа ta:

The total number = 100

Families that got their news from TV = 60

Families that got their news from local paper = 54

Families that got their news from both TV and local paper = 20

The probability that family does not use any one of these sources for the news = 1 - probability of the event

If a family is selected at random, the probability that this family does not use any one of these sources for the news = 1 - (The probability that a selected family get news from either TV or from local paper)

If a family is selected at random, the probability that this family does not use any one of these sources for the news = 1 - (60/100 + 54/100 - 20/100)

= 1 - (94/100)

= 1 - 0.94

=0.06

If a family is selected at random, the probability that this family does not get news from either TV or from local paper = 6% or 6/100