Two students in a behavioral sciences class compared their scores on a series of five quizzes. Which student tended to perform better on the quizzes? Which student tended to perform more consistently on the quizzes?

Question

Social Studies

Jolly

14 June, 12:31

Two students in a behavioral sciences class compared their scores on a series of five quizzes. Which student tended to perform better on the quizzes? Which student tended to perform more consistently on the quizzes?

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Answers (2)

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Terrance Sloan · Answer 1

The student who had the best performance in the tests was the one who had the highest score. The student who performed more consistently on the tests was the one who scored similarly on each test.

Explanation:

In the question above, we are informed that each student has been subjected to five tests. After receiving the scores these students went to compare their performance with each other.

Let's assume that each test was worth a score from 1 to 10.

Student A had the following scores: 1, 3, 5,10,10.

Student B had the following scores: 4,5,4,4,4.

As you can see, student A scored higher than student B in almost all tests, leaving his average score higher than student B, this shows that student A had a better performance in the tests.

However, student B had a performance with very similar and even equal scores in each test, showing a more consistent and balanced performance, since he maintained equivalent knowledge in each test.

Clare Chavez · Answer 2

complete question:

Two students in a behavioral sciences class compared their scores on a series of five quizzes. Which student tended to perform better on the quizzes? Which student tended to perform more consistently on the quizzes?

student x : 4, 9, 3, 8, 9

student y : 6, 5, 7, 5, 6

Answer:

a. We can conclude that student x perform better than student y in the quizzes.

b. Student y tend to perform more consistently on the quizzes.

Explanation:

Which student tended to perform better on the quizzes?

Using the mean score we can know the student that performs better. Therefore let's calculate the mean of each student.

student x

mean = 4 + 9 + 3 + 8 + 9/5 = 33/5 = 6.6

student y

mean = 6 + 5 + 7 + 5 + 6 / 5 = 29/5 = 5.8

We can conclude that student x perform better than student y in the quizzes.

b. Which student tended to perform more consistently on the quizzes?

Student y tend to perform more consistently on the quizzes. There is more homogeneity in the score of student y and more heterogeneity in the score of student x. The score of student x range from 3 to 9, so it covers more range while student y score range from 5 to 7 which is more consistent.