G (x) = ax2+24

For the function g defined above, a is a constant and g (4) = 8. What is the value of g (-4) ?

So, Im assuming the x2 is x², if so then the answer would be

G (4)

Ax²+24=8

we replace the x with the value of 4 since we're given the answer

A (4) ²+24=8

and then we try and solve the equation, first we need to get rid of the square which is (4) ² thats the same as 4*4 thats equal to 16, so our equation would look like this

A (16) + 24=8

then we carry on to try an look for (A), we can start by getting the difference between 24 and 8 so we move it to the other side as a - 24 and get this

16 (A) = 8 - 24

which would basically be by adding a - 24 to both sides so we can get rid of the + 24, and we get the same equation as above

16 (A) + 24 - 24 = 8 - 24

16 (A) = - 16

then we need look for (A) by dividing both sides to 16

16 (A) / 16 = - 16/16

and we get that (A) = - 1

so with that now we can look for the value of G (-4)

first we form our new equation with the value of A and the new value of G which is - 4, now since we are dealing with a square it doesnt matter if (x) its positive or negative since it doesnt really affect the previous result (4) ²=16 and (-4) ²=16, but for the sake of it lets try to do it

G (-4)

A (-1)

ax²+24

so we replace with the values already obtained (A) and (x)

(-1) (-4) ²+24

as stated before the

(-1) (16) + 24

and all thats left is this

-16+24

and the answer to the question would be 8