Freckles is dominant over no freckles. what percentage of offspring would be predicted to have freckles if the father was heterozygous for freckles and the mother did not have freckles

The answer would be 50%.

Let's make a Punnett square for this:

Let F - Freckles

f - no freckles

Father: Ff

Mother: ff (She has no freckles, meaning she does not have the dominant allele)

F f

f Ff ff

f Ff ff

The count would then be 2/4 with freckles and 2/4 without freckles. So the percentage of would be 50% with freckles and 50% without freckles.