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20 December, 15:21

In sheep, the allele for belly fur (A) is dominant to the allele for no belly fur (a). A mother with the genotype As and the father with the genotype As produce an offspring. What is the percent chance the offspring with have no belly fur

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  1. 20 December, 18:29
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    25%

    Explanation:

    In sheep, the allele for belly fur (A) is dominant to the allele for no belly fur (a). A mother with the genotype Aa and a father with the genotype Aa produce an offspring. What is the percent chance that the offspring will have NO belly fur?

    Allele A is dominant over allele a.

    Genotype of mother = Aa

    Genotype of father = Aa

    Crossing Aa and Aa:

    Aa x Aa = AA, 2Aa, and aa

    Since A is dominant over a, both AA and Aa have belly fur.

    Hence, the ratio of the offspring with belly fur to those without belly fur is 3:1.

    Percentage of the offspring without belly fur is 25%.
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