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16 December, 12:34

Lino is a linebacker on his college football team. he is concerned about achieving adequate hydration during intense, hot summer football practices. lino weighs himself before and after practice and notices that he loses five pounds by the time practice is over. about how much water would be enough to replace these fluid losses?

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  1. 16 December, 13:27
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    2 quarts, 1 cup, 5 ounces. or about 5 pints. If Lino's losses are just due to water, then the problem can be rephrased as "What volume of water would it take to weight five pounds?" So, let's figure that out. Since the problem is stated in imperial units, the answer will also be in imperial units. But since the easiest source of the mass of water is metric, the problem will be using quite a few conversion factors to and from metric. Initial known facts Water masses about 1 gram per cubic centimeter, Conversion factors 1 pound = 0.453592 kilograms 1 liter = 0.264172 gallons Since we have 5 pounds, let's convert that to kilograms. 5 lb * 0.453592 kg/lb = 2.26796 kg And since 1 liter of water weight about 1 kilogram, that means we need 2.26796 liters of water. Now convert to gallons. 2.26796 l * 0.264172 gal/l = 0.599131529 gal Now there's 128 ounces in a gallon, so 0.599131529 gal * 128 oz/gal = 76.68883573 oz Rounding up to 77 ounces of water. Since there's 8 ounces per cup, we can divide and get 9 cups, 5 ounces Since there's 2 cups per pint, we can say 4 pints, 1 cup, 5 ounces And finally since there's 2 pints per quart, we can say 2 quarts, 1 cup, 5 ounces. Or since you're interested in an approximate amount, you can remember the mnemonic "a pint's a pound the world around." and using that mnemonic, figure that since he lost 5 pounds, he lost about 5 pints of fluid. So he needs 5 pints of fluid to restore himself.
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