A produce supplier ships boxes of produce to individual customers. The distribution of weights of shipped boxes is approximately normal with mean 36 pounds and standard deviation 4 pounds. Which expression represents the weight, in pounds, at the 75th percentile of the distribution?

36 + (4 * 0.67)

Explanation:

Data provided:

Mean weight of the boxes = 36 pounds

standard deviation of weight of boxed = 4 pounds

75th percentile

Now,

From the percentile vs z-score table

for 75th percentile, z-score = 0.67

also,

75th percentile distribution = Mean + (standard deviation * z-score)

or

75th percentile distribution = 36 + (4 * 0.67)