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9 November, 12:14

Elizabeth Airlines (EA) flies only one route: Chicagolong dash-Honolulu. The demand for each flight is: Upper Q equals 500 minus Upper PQ=500-P. EA's cost of running each flight is $30,000 plus $100 per passenger. What is the profit-maximizing price that EA will charge? How many people will be on each flight? What is EA's profit for each flight? (round all answers to a whole number)

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  1. 9 November, 13:41
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    Profit-maximizing price = $300

    People on flight = 200 people per flight

    Profit for each flight = $10,000

    Explanation:

    As per the data given in the question,

    Demand curve in inverse form:

    P = 500 - Q

    We know that marginal revenue curve for a linear demand curve will twice the slope,

    So Marginal Revenue = 500 - 2Q

    Marginal cost of carrying per passenger = $100

    To determine profit maximizing quantity, Equating Marginal Revenue to Marginal Cost

    Let the people on each flight be Q, then

    500 - 2Q = 100

    Q = 200 people per flight

    Substituting the value Q in demand equation to find profit maximizing price for each ticket

    Profit Maximizing price (P) = $500 - $200

    = $300

    Profit for each flight = Total Revenue - Total Cost

    = (300) (200) - (30,000 + (200) (100))

    = $10,000 per flight
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