You have a racemic mixture of d-2-butanol and l-2-butanol. the d isomer rotates polarized light by + 13.5∘. what is the rotation of the polarization of light of your mixture? express your answer in degrees.

L - isomer is considered as the Enantiomer of d - isomer and since the d-isomer optical rotation is + 13.5° so the optical rotation of l-isomer will be the same degree but with opposite sign which equal to - 13.5°

So the degree of rotation of racemic mixture will equal 0°

- This is because racemic mixture contains equal amount of both enantiomers