A 0.100-l sample of an unknown hno3 solution required 32.9 ml of 0.200 m ba (oh) 2 for complete neutralization. what was the concentration of the hno3 solution?

The reaction between HNO3 and Ba (OH) 2 is given by the equation below;

2HNO3 + Ba (OH) 2 = Ba (NO3) 2 + 2H2O

Moles of Barium hydroxide used;

= 0.200 * 0.039 l

= 0.0078 Moles

The mole ratio of HNO3 and Ba (OH) 2 is 2: 1

Therefore; moles of nitric acid used will be;

= 0.0078 * 2 = 0.0156 moles

But; 0.0156 moles are equal to a volume of 0.10

The concentration of Nitric acid will be;

= (0.0156 * 1) / 0.1

= 0.156 M