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8 October, 21:32

What is the molarity of the two solutions

0.150 mol of NaOH in 1.80 L of solution

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  1. 8 October, 23:41
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    1 mole of MgS = 24.3 + 32.1 = 56.4 g

    35.1 g MgS x 1 mol / 56.4 g = 0.622 mol

    M = 0.622 mol / 0.835 L = 0.745 mol/L
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