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8 October, 21:42

The specific heat of aluminum is 0.897j / (g•°C). If a 22.6 g sample of aluminum is heated from 25°C to 250°C, then how much heat will the aluminum absorb?

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  1. 9 October, 00:19
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    Q=mcat

    = (22.6) (.897) (250-25)

    4,561.245 or 4.5 * 10^-3
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