What mass of silver ag which has an atomic mass of 107.87 amu contains the same number of atoms contained in 10.0g of boron b which has an atomic mass of 10.81 amu?

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Chemistry

Shields

8 June, 20:01

What mass of silver ag which has an atomic mass of 107.87 amu contains the same number of atoms contained in 10.0g of boron b which has an atomic mass of 10.81 amu?

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Kaleigh Roberson · Answer 1

To contain the same number of atoms also mean to contain the same number of moles. So let us say that X is the mass of Silver Ag required, so that:

X / 107.87 = 10 / 10.81

X = 99.79 g