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Today, 02:24

How many kilojoules of energy are absorbed when 800.0g of water is heated from 20.0º C to 50.0º C

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  1. Today, 03:11
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    Answer is: 100,464 kJ energy are absorbed.

    m (water) = 800,0 g.

    T₁ = 20°C.

    T₂ = 50°C.

    ΔT = T₂ - T₁.

    ΔT = 50°C - 20°C.

    ΔT = 30°C.

    c (water) = 4,186 J/g·°C.

    Q = m · c · ΔT.

    Q = 800 g · 4,186 J/g·°C · 30°C.

    Q = 100464 J = 100,464 kJ.

    c - specific heat of water.
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