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30 September, 02:55

2. The pressure of the oxygen gas inside a

canister is 5.00 atm at 25 degrees C. The

canister is placed in a freezer. If the

temperature falls to - 10 degrees Celsius,

what is the new pressure inside the canister?

3,41 atm

12.5 atm

4.41 atm

12.5 atm

+4
Answers (1)
  1. 30 September, 03:36
    0
    Answer: 4.41 atm

    Explanation:

    Given that,

    Original pressure of oxygen gas (P1) = 5.00 atm

    Original temperature of oxygen gas (T1) = 25°C

    [Convert 25°C to Kelvin by adding 273

    25°C + 273 = 298K

    New pressure of oxygen gas (P2) = ?

    New temperature of oxygen gas (T2) = - 10°C

    [Convert - 10°C to Kelvin by adding 273

    -10°C + 273 = 263K

    Since pressure and temperature are given while volume is held constant, apply the formula for Charle's law

    P1/T1 = P2/T2

    5.00 atm / 298K = P2/263K

    To get the value of P2, cross multiply

    5.00 atm x 263K = 298K x V2

    1315 atm•K = 298K•V2

    V2 = 1315 atm•K / 298K

    V2 = 4.41 atm

    Thus, the new pressure inside the canister is 4.41 atmosphere
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