Ask Question
1 January, 09:33

32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa) ?

+4
Answers (1)
  1. 1 January, 10:53
    0
    Under standard temperature and pressure conditions, it is known that 1 mole of a gas occupies 22.4 liters.

    From the periodic table:

    molar mass of oxygen = 16 gm

    molar mass of hydrogen = 1 gm

    Thus, the molar mass of water vapor = 2 (1) + 16 = 18 gm

    18 gm of water occupies 22.4 liters, therefore:

    volume occupied by 32.7 gm = (32.7 x 22.4) / 18 = 40.6933 liters
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “32.7 grams of water vapor takes up how many liters at standard temperature and pressure (273 K and 100 kPa) ? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers