how many grams of barium sulfate will be formed upon the complete reaction of 25.6 grams of barium hydroxide with excess sulfuric acid?

Mass of barium sulfate produced = 35.007 g

Explanation:

Given dа ta:

mass of Ba (OH) ₂ = 25.6 g

mass of barium sulfate = ?

Solution:

First of all we will write the balance chemical equation:

Ba (OH) ₂ + H₂SO₄ → BaSO₄ + 2H₂O

Number of moles of Ba (OH) ₂ = mass/molar mass

Number of moles of Ba (OH) ₂ = 25.6 g / 171.34 g/mol

Number of moles of Ba (OH) ₂ = 0.15 mol

Now we will compare the moles of barium sulfate with barium hydroxide.

Ba (OH) ₂ : BaSO₄

1 : 1

0.15 : 0.15

Mass of Barium sulfate:

Mass = number of moles * molar mass

Mass = 0.15 mol * 233.38 g/mol

Mass = 35.007 g