Assume that 13.5 g solid aluminum (Al) react with HCl to produce solid aluminum chloride (AlCl3) salt and gaseous hydrogen (H2) at standard temperature and pressure. How many moles of Al react? mol How many moles of H2 are produced? mol How many liters of H2 are produced? L

Hello

The balance chemical reaction is 2Al + 6HCl - à 2AlCl3 + 3H2 Assuming excess amount of HCl because it is not given Mole Al reacted = 13.5 g (1 mole / 27 g) = 0.5 mole Al

Mole H2 = 0.5 mol Al (3 mole H2 / 2 mole Al) = 0.75 mole H2

since at STP then 1 mole gas occupies 22.414 L volume H2 = 0.75 mole (22.414 L / mol) = 16.8105 L H2

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