You have separate solutions of hcl and h2so4 with the same concentrations in terms of molarity. you wish to neutralize a solution of naoh. which acid solution would require more volume (in ml) to neutralize the base?

HCl + NaOH = NaCl + H₂O

H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O ⇒ 0.5H₂SO₄ + NaOH = 0.5Na₂SO₄ + H₂O

V (HCl) = 2V (H₂SO₄)

The volume of the hydrochloric acid solution (HCl) is twice as large as the volume of the sulfuric acid solution (H ₂SO₄).