A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the sample of mf2 that forms?

Question

Chemistry

Marina

24 July, 04:57

A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the sample of mf2 that forms?

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Karsyn Stewart · Answer 1

The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

moles MF2 produced = 0.600 mol M (1 mol MF2 / 1 mol M) = 0.600 mol MF2

molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol

moles MF2 = 46.8 g (1 mol / 78 g) = 0.6 mol

moles F = 0.6 mol MF2 (2 mol F / 1 mol MF2) = 1.2 moles F