Ask Question
10 February, 15:36

What is the volume of oxygen occupied by 2 moles at 1.3 atm pressure and 300 K? Use PV = nRT.

+2
Answers (2)
  1. 10 February, 18:14
    0
    We can use the ideal gas law equation to find the volume occupied by O₂

    PV = nRT

    where P - pressure - 1.3 atm x 101 325 Pa/atm = 131 723 Pa

    V - volume

    n - number of moles - 2 mol

    R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

    T - temperature - 300 K

    Substituting these values in the equation

    131 723 Pa x V = 2 mol x 8.314 Jmol⁻¹K⁻¹ x 300 K

    V = 37.9 L

    volume occupied is 37.9 L
  2. 10 February, 18:35
    0
    The volume of oxygen gas that occupied by 2 moles at 1.3 atm pressure and 300 k is calculated using the ideal gas equation that is Pv = nRT

    P (pressure) = 1.3 atm

    R (gas constant) = 0.082 l. atm/mol. k

    n (moles) = 2 moles

    T (temperature) = 300k

    V (volume) = ?

    by making the v the subject of the formula V = nRT/P

    = (2 moles x 0.082 l. atm/mol. k x300 K) / 1.3 atm = 37.85 Liters
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the volume of oxygen occupied by 2 moles at 1.3 atm pressure and 300 K? Use PV = nRT. ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers