How many grams of sucrose (c12h22o11) are in 1.55 l of 0.758 m sucrose solution? express your answer in grams to three significant figures?

The molecular formula of sucrose is - C₁₂H₂₂O₁₁

molecular mass of sucrose - 342 g/mol

molarity of sucrose solution is 0.758 M

In 1 L solution the number of sucrose moles are - 0.758 mol

Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L

= 1.17 mol

The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g