Calculate the solubility (in g/l) of silver chromate in water at 25°c if the ksp for ag2cro4 is 1.1 * 10-12. 2.7 * 10-2 g/l 2.2 * 10-2 g/l 3.4 * 10-2 g/l 3.5 * 10-4 g/l

Question

Chemistry

Kyler Marsh

21 October, 21:32

Calculate the solubility (in g/l) of silver chromate in water at 25°c if the ksp for ag2cro4 is 1.1 * 10-12. 2.7 * 10-2 g/l 2.2 * 10-2 g/l 3.4 * 10-2 g/l 3.5 * 10-4 g/l

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Viviana Ortega · Answer 1

Answer is: solubility of silver chromate is 2.2 * 10-2 g/l.

Chemical reaction (dissociation) of silver chromate in water:

Ag ₂CrO₄ (s) → 2Ag⁺ (aq) + CrO₄²⁻ (aq).

Ksp (Ag ₂CrO₄) = [Ag⁺]²·[CrO₄²⁻].

[CrO ₄²⁻] = x.

[Ag ⁺] = 2[CrO₄²⁻] = 2x

1,1 ·10⁻¹² = (2x) ² · x = 4x³.

x = ∛1,1·10⁻¹² : 4.

x = 6,5·10⁻⁵ M.

solubility of silver chromate: 6,5·10⁻⁵ mol/L · 331,73 g/mol = 0,022 g/L.

Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.

[Ag ⁺] is equilibrium concentration of silver cations.

[CrO ₄²⁻] is equilibrium concentration of chromate anions.