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27 July, 03:27

If the ka of a monoprotic weak acid is 1.0 * 10-6, what is the ph of a 0.50 m solution of this acid?

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  1. 27 July, 07:07
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    Answer is: pH value of weak acid is 3.15.

    Chemical reaction: HA (aq) ⇄ A⁻ (aq) + H⁺ (aq).

    c (weak acid) = 0,5 M.

    Ka (weak acid) = 1.0 ·10⁻⁶.

    [A⁻] = [H⁺] = x.

    [HA] = 0.5 M - x.

    Ka = [A⁻]·[H⁺] / [HA].

    1.0·10⁻⁶ = x² / (0,5 M - x).

    Solve quadratic equation: x = [H⁺] = 0.0007 M.

    pH = - log[H⁺].

    pH = - log (0.0007 M).

    pH = 3.15.
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