A 100.5 ml intraveneous (iv) solution contains 5.10 g glucose (c6h12o6). what is the molarity of this solution?

Question

Chemistry

Camden Horne

13 October, 19:30

A 100.5 ml intraveneous (iv) solution contains 5.10 g glucose (c6h12o6). what is the molarity of this solution?

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Kiersten Fry · Answer 1

Answer is: the molarity of this glucose solution is 0.278 M.

m (C₆H₁₂O₆) = 5.10 g.

n (C₆H₁₂O₆) = m (C₆H₁₂O₆) : M (C₆H₁₂O₆).

n (C₆H₁₂O₆) = 5.10 g : 180.156 g/mol.

n (C₆H₁₂O₆) = 0.028 mol.

V (solution) = 100.5 mL : 1000 mL/L.

V (solution) = 0.1005 L.

c (C₆H₁₂O₆) = n (C₆H₁₂O₆) : V (solution).

c (C₆H₁₂O₆) = 0.028 mol : 0.1005 L.

c (C₆H₁₂O₆) = 0.278 mol/L.