Calculate the density (in g/l) of ch4 (g) at 75 c and 2.1 atm. (r = 0.08206 latm/molk

Question

Chemistry

Efrain Zimmerman

25 November, 16:36

Calculate the density (in g/l) of ch4 (g) at 75 c and 2.1 atm. (r = 0.08206 latm/molk

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Carmelo · Answer 1

Answer is: density of methane is 1.176 g/L.

V (CH ₄) = 1 L.

T = 75°C = 348.15 K.

p = 2.1 atm.

R = 0.08206 L·atm/mol·K.

Ideal gas law: p·V = n·R·T.

n = p·V / R·T.

n (CH₄) = 2.1 atm · 1 L / 0.08206 L·atm/mol·K · 348.15 K.

n (CH₄) = 0.0735 mol.

m (CH₄) = n (CH₄) · M (CH₄).

m (CH₄) = 0.0735 mol · 16 g/mol.

m (CH₄) = 1.176 g.

d (CH₄) = m (CH₄) : V (CH₄).

d (CH₄) = 1.176 g/L.