2Al (s) + 3Pb (N03) 2 (aq) 2Al (N03) 3 (aq) + 3Pb (s) How many molecules of Pb (N03) 2 are used in the reaction? How many oxygen atoms are used in the reaction? How many moles of Al (N03) 3 are formed? What is the mole ratio of Pb (N03) 2 to Al (N03) 3?

A. 1.806x10^24 molecules of Pb (NO3) 2

B. 18 oxygen atoms.

C. 2 moles of Al (NO3) 3.

D. The mole ratio of Pb (N03) 2 to Al (N03) 3 is 3 : 2

Explanation:

The balanced equation for the reaction is given below:

2Al (s) + 3Pb (NO3) 2 (aq) - > 2Al (NO3) 3 (aq) + 3Pb (s)

A. Determination of the number molecules of Pb (NO3) 2 used in the reaction. This is illustrated below.

From the balanced equation above, 3 moles of Pb (NO3) 2 were used in reaction.

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. This means that 1 mole of Pb (NO3) 2 contains 6.02x10^23 molecules.

Now, if 1 mole of Pb (NO3) 2 contains 6.02x10^23 molecules,

then, 3 moles of Pb (NO3) 2 will contain = 3 x 6.02x10^23 = 1.806x10^24 molecules.

Therefore, 1.806x10^24 molecules of Pb (NO3) 2 is used in the reaction.

B. Determination of the number of oxygen atom used in the reaction.

This is illustrated below:

To obtain the number of oxygen atom used in the reaction, we simply do a head count of the oxygen atom in the reactant.

The reactant containing oxygen is Pb (NO3) 2 and there are 3 moles of it according to the balanced equation.

There are a total of 18 oxygen atom in 3 moles of Pb (NO3) 2. Therefore, 18 oxygen atoms are used in the reaction.

C. Determination of the number of mole of Al (NO3) 3 formed.

From the balanced equation above, 2 moles of Al (NO3) 3 are formed

D. Determination of the mole ratio of Pb (N03) 2 to Al (N03) 3

From the balanced, 3 moles of Pb (N03) 2 reacted and 2 moles of Al (N03) 3 are produced.

Therefore, the mole ratio of Pb (N03) 2 to Al (N03) 3 is 3 : 2