Samples of f2 gas and xe gas are mixed in a container of fixed volume. the initial partial pressure of the f2 gas is 8.0 atmospheres and that of the xe gas is 1.7 atmospheres. when all of the xe gas reacted, forming a solid compound, the pressure of the unreacted f2 gas was 4.6 atmospheres. the temperature remained constant. what is the formula of the compound?

Question

Chemistry

Guest

10 October, 00:53

Samples of f2 gas and xe gas are mixed in a container of fixed volume. the initial partial pressure of the f2 gas is 8.0 atmospheres and that of the xe gas is 1.7 atmospheres. when all of the xe gas reacted, forming a solid compound, the pressure of the unreacted f2 gas was 4.6 atmospheres. the temperature remained constant. what is the formula of the compound?

+5

Answers (1)

Know the Answer?

Gilbert · Answer 1

Answer is: XeF₄.

p₁ (F₂) = 8,0 atm.

p₁ (Xe) = 1,7 atm.

p₂ (F₂) = 4,6 atm.

p₂ (Xe) = 0 atm, all reacted.

p - partial pressure.

pressure of F₂ reacted = Δp (F₂) = 8.0 - 4.6 = 3.4 atm.

pressure of Xe reacted = Δp (Xe) = 1,7 - 0 = 1,7 atm.

Δp (F₂) / Δp (Xe) = 3,4 atm / 1,7 atm = 2:1.

Reaction: 2F₂ + Xe → XeF₄ (xenon-tetrafluoride)