If the reaction of 5.87 moles of potassium with excess hydrobromic acid produced an 84.8% yield of hydrogen gas, what was the actual yield of hydrogen gas?

Question

Chemistry

Yasmin Graham

13 November, 06:30

If the reaction of 5.87 moles of potassium with excess hydrobromic acid produced an 84.8% yield of hydrogen gas, what was the actual yield of hydrogen gas?

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Answers (1)

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Immanuel Glover · Answer 1

Answer is: 2,488 mol.

Chemical reaction: 2K + 2HBr → 2KBr + H₂.

n (K) = 5,87mol.

%product = 84,8% = 0,848.

n (H₂) = ?

n - amount od substance.

n (K) : n (H₂) = 2 : 1.

5,87 mol : n (H₂) = 2:1.

n (H₂) = 2,935 mol, if reaction is 100%.

actual moles 0,848 · 2,935 mol = 2,488 mol.