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8 March, 02:38

At 25.0∘C, the molar solubility of barium chromate in water is 1.10*10-5 M. Calculate the solubility in grams per liter.

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  1. 8 March, 02:58
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    Hey there!

    Molar mass:

    ‎BaCrO 4 = ‎253.319 g/mol

    (g/L) = molar solubility * molar mass

    (g/L) = (1.10 x 10⁻⁵) * 253.319

    => 2.79x10⁻³ g/L
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