What mass of AgCl is produced when 53.42 g of AgNO3 reacts with 14.19 g of NaCl?

Question

Chemistry

Randall Huffman

27 January, 00:43

What mass of AgCl is produced when 53.42 g of AgNO3 reacts with 14.19 g of NaCl?

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Answers (1)

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Larry Mullen · Answer 1

Answer is: mass of silver chloride is 34,82 g.

Chemical reaction: AgNO₃ + NaCl → AgCl + NaNO₃.

m (AgNO ₃) = 53,42 g ...

m (NaCl) = 14,19 g.

n (AgNO ₃) = m (AgNO₃) : M (AgNO₃).

n (AgNO ₃) = 53,42 g : 169,87 g/mol.

n (AgNO₃) = 0,314 mol.

n (NaCl) = 14,19 g : 58,4 g/mol.

n (NaCl) = 0,242 mol; limiting reactant.

From chemical reaction: n (NaCl) : n (AgCl) = 1 : 1.

n (AgCl) = 0,242 mol.

m (AgCl) = 0,252 mol · 143,32 g/mol.

m (AgCl) = 34,82 g.