The solid in question 2 was aluminum sulfate, al2 (so4) 3. calculate the molar heat of solution, δhsoln, for aluminum sulfate. hint: the units for molar heat of solution are kilojoules per mole (kj/mole). first determine the heat released per gram of solid.

The solution for this problem is:

The information given lacks but nevertheless the answer is:

So, the total heat free by dissolving the solute was 1386 + 32 = 1417 J

Then, dissolving of the solute will have released - 1417 J. So, per gram of Al2 (SO4) 3 dissolved:

-1417 J / 25 g = - 56.7 J/g

Translating that to a per mole: - 56.7 J/g X 342 g/mol = - 1.94X10^4 J/mol = - 19 kJ/mol = this would be Delta Hsoln