The volume occupied by 9.03*10^23 molecules of N2 gas at STP is closest to?

A) 1.50 L

B).500 L

C) 22.4 L

D) 33.6 L

The answer would be D

D) 33.6 l

Explanation:

First convert from molecules of N2 gas to moles of N2 gas:

9.03 x 10^23 molecules N2 x (1 mole / 6.022x10^23 molecules) = 1.499501827 mol N2

Next,

Use the ideal gas equation:

PV = nRT

At STP conditions,

P = 1 atm

V = x

n = 1.499501827 mol N2

R = 0.08206 atm L / mol K

T = 273.15 K

Solve for V

PV = nRT

V = nRT / P = 33.6108671 L = 33.6 L