How many grams of beryllium are needed to produce 36.0 g of hydrogen assume an excess of waater be (s) + 2h2o (l) be (oh) 2 (aq) + h2 (g) ?

Question

Chemistry

Easton Keller

28 July, 13:33

How many grams of beryllium are needed to produce 36.0 g of hydrogen assume an excess of waater be (s) + 2h2o (l) be (oh) 2 (aq) + h2 (g) ?

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America Crawford · Answer 1

Answer is: 162 g of beryllium.

Chemical reaction: Be + 2H₂O → Be (OH) ₂ + H₂.

m (H₂) = 36,0 g.

m (Be) = ?

n (H₂) = m (H₂) : M (H₂)

n (H₂) = 36,0 g : 2 g/mol = 18 mol.

from reaction: n (Be) : n (H₂) = 1 : 1.

n (Be) = n (H₂) = 18 mol.

m (Be) = n (Be) · M (Be).

n (Be) = 18 mol · 9 g/mol = 162 g.