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11 December, 19:54

An ideal gas occupies a volume of 2.70 l at 2.80 atm and 28°c. if the temperature is raised to 36°c and the pressure is decreased to 1.30 atm, what is the final volume of the gas?

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  1. 11 December, 23:45
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    It is already stated in the given that the gas is ideal such that it will follow through the equation,

    PV = nRT

    If all else are equal except for the temperature and pressure, the equation that relates the initial and final conditions.

    P₁V₁/T₁ = P₂V₂/T₂

    Substituting the known values,

    (2.80 atm) (2.70 L) / (28 + 273.15) = (1.30 atm) (V₂) / (36 + 273.15)

    The value of V₂ is 5.97 L.

    Answer: 5.97 L
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