Determine the molality of an aqueous solution that is 15.5 percent urea by mass.

15.5% by mass is equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution.

we know that molality = moles solute / kg solvent

moles solute = 155 g / 60 g/mol = 2.58 moles urea

Since there are 155 g urea in 1000g solution, hence the solvent is 845 g or 0.845 kg

So:

molality = 2.58 / 0.845 = 3.06 m