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12 March, 08:19

How many lithium ions are present in 30.0 ml of 0.600 m li2co3 solution?

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  1. 12 March, 10:17
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    First; use the relationship of molarity and moles/liter to find the moles of the solution.

    so 0.600M * 0.030L = 0.018 moles

    Then use the mole to mole ratio of lithium to lithium carbonate

    0.18 * (2 Li : 1 Li2CO3) = 0.036

    and then multiply by Avogadro's number to find the ions of lithium

    0.036 moles * (6.022*10^{23}) = 2.167 * 10∧22 ions Li
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